During my days as a student, algebra always seemed to be one of my favourite topics. I found it very straight forward, easy to understand… so long as you have a strong foundation in basic Maths. In algebra, students must be dared enough to adopt self experiment and apply bracket whenever necessary. This will help a lot…. just take this piece of advice whenever you come across problem that requires algebra as a way of solution.

Today, I’m going to share with you amongst the common problems faced by most students when come to algebra.

The most popular ones is failure to expand the equation properly. Clear example is as follows :

Another common mistake is failure to differentiate between one equation to another. For example;

x² – y² IS NOT THE SAME WITH ( x – y )²

In cases like this, students are encouraged to do their own experiment; by way of replacing x and y with simple digits. For instance, let x = 5 and y = 2

x² – y² shall now read as 5² – 2² = 25 – 4 = **21**

Now compare with the other equation

( x – y )² = ( 5 – 2 )² = (3)² = **9**

From the experiment above, it shows clearly that

**x² – y² IS NOT THE SAME WITH ( x – y )²**

To master this topic will not take too much of time, just put extra effort on exercise and if there is any particular tips that ought to be given attention…that has to be

**x² – y² = ( x + y )( x – y ) **

**or 16x² – 4y² = 4²x² – 2²y² = (4x + 2y )( 4x – 2y )**

AND

**x² + y² = ( x + y )² – 2xy**

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Misheck Njabili

said:I have problems in solving Maths

unclezul

said:Do you mean pproblems in solving algebraic expression or Maths as a whole? If you wish for my help in algebraic expression, please post me some question and I’ll be more than glad to show you the steps in solving the problems. Looking forward to your reply

madhuraa

said:5m=4n-3

unclezul

said:I don’t really get your question but I presume it may ask for either one of the followings:

i. Finding m in term of n :

5m = 4n – 3

since you only wish to maintain m on one side, therefore the only way to get rid of 5 is by way of dividing 5M with 5. As such the other side of equation 4n – 3 must be divided by 5 as well

m = (4n – 3)/5

ii. Finding n in term of m:

5m = 4n – 3

5m + 3 = 4n

4n = 5m + 3

n = (5m + 3)/4

unknown

said:help me to solve this : (a-3b)(2c+5d)

unclezul

said:(a-3b)(2c+5d) = a(2c+5d)-3b(2c+5d)

= 2ac+5ad-6bc-15bd

where

2ac derived from a x 2c

+5ad derived from a x +5d

-6bc derived from -3b x 2c

-15bd derived from -3b x +5d

remember the following basis :

(a+b)(c-d) = a(c-d)+b(c-d)

= ac-ad+bc-bd

kindly take note on the +ve and -ve value of each number

Good luck unknown…. 🙂

plez help me

said:how to solve this question? (h-5)(3h plus 2)

unclezul

said:(h-5)(3h+2) give you the indicates both numbers represented in bracket form must be multiplied to each other. For example (m)(n-p) = mn – mp

As such, (h-5)(3h+2) = h(3h+2)-5(3h+2) = 3h² + 2h – 15h – 10 = 3h² – 13h – 10

Operation involving Algebraic Expression is rather simple, the only thing that may require concentration probably will be the value of + or -.

Please take note on the following differences:

(m-n)(p+q) = m(p+q)-n(p+q)= mp+mq-np-nq

(m-n)-(p+q) = m-n-p-q

Let me know if you require further explanation

rahman

said:cikgu you said

16x² – 4y² = 4²x² – 2²y² = (4x + 2y )( 4x – 2y )

but it supposed to be 4(4x^2-y^2)= 4(2^2x^2-y^2)=4(2x+y)(2x-y)

unclezul

said:16x² – 4y² = 4²x² – 2²y² = (4x + 2y )( 4x – 2y )

If you expand (4x + 2y )( 4x – 2y ), it will give you 4x(4x-2y)+2y(4x-2y)

then it will be 16x² – 8xy + 8xy -4y² = 16x² – 4y²

ain zaharudin(aen)

said:How can I thingking it is easy? Can you learn me more detail about it?

unclezul

said:Hi Aen, tengok contoh contoh yang uncle dah tunjukkan. Kaji setiap langkah dan InsyaAllah Aen akan mampu menguasainya. Tajuk ni tak lah sesusah yang dikatakan

Diyanah

said:cikgu can you help me to solve this…

Given that x = 8-5y² , hence y=

unclezul

said:Hi Diyanah, you are require to find the value of y in terms of x.

In this situation, what you need to do is to neutralize all the numbers and operations involving y as follows:

8 – 5y^2 = x

5y^2 = 8 – x >>>>>> shift all the numbers without y to one side

y^2 = (8 – x)/5>>>>>> divide by 5 for both sides in order to neutralize 5y^2

y = √ (8 – x)/5 >>>> square root both sides in order to neutralize y^2

There you have it!!! Mudahkan?

Nur atiqah

said:I have problem in mathematic.i hope teacher will give me a tips for mathemathic

unclezul

said:Dear Nur atiqah, I dont really believe that you’ve such a problem. Probably you are not guided in the right way…if you still face difficulty in solving Maths, please do not hesitate to communicate with me. InsyaAllah Uncle akan cuba bantu sedaya yang boleh

Diyanah

said:hehe thank you cikgu 🙂

fathin farisha

said:cikgu ? soalan mathematics . .

(a) x = 13 – y , x – y = 3

fathin farisha

said:sya tak tahu macam mna nk buat

unclezul

said:Hi Fathin,

soalan macam ni bawah tajuk Simultaneous Equation;

x = 13 – y ……..(1) ; x – y = 3 ………(2)

Langkah pertama: Gantikan nilai (1) dalam (2);

(13 – y) – y = 3

13 – 2y = 3

13 – 3 = 2y

10 = 2y

10/2 = y

y = 5

Langkah Kedua: Gantikan y = 5 dalam (1) atau (2)

Dalam soalan ni, Uncle gantikan dalam (1)

x = 13 – 5

x = 8

Jawapan: x=8 dan y=5

MUDAHKAN?

angel sri

said:erhhhh…i don’t understand d part factorisation ..m so scared for pmr…

plz can u guide me in factorisation …

tolong cikgu…

angel sri

said:give me ur own questions and examples…plzzzzzzzzzzzzz…. >_<

unclezul

said:InsyaAllah…unfortunately, uncle a little bit busy nowadays. Perhaps soon…

angel sri

said:owh…okey….sorry 4r d disturbances..

Mitxun

said:Hi angel sri Can you help me on the problems how will be the exampls

|n-m|+|n+k|-|m-k| if will be m>n>k>0

thanks

unclezul

said:Since your question appear on the Form 3 syllabus, I assume that the equation is written as follows:

(n-m)+(n+k)-(m-k) = n-m+n+k-m+k = 2n-2m+2k

In the relation of m>n>k>0; all of the integers are positive where k is the smallest, follow by n and m is the largest. As such the order ascending order of the number shall be in the form of 0,k,n and m.

NanaReanna

said:Can you help me? We should go for a talk @ email .please reply me if u’re online now.

tQ

shalini

said:how about 3/4(a+b)

unclezul

said:3/4(a) + 3/4(b) = (3a+3b)/4

anis

said:1/a+1/b=1/c (b)

cikgu rumus utk b ap ?

unclezul

said:(b+a)/ab = 1/c

c(b+a) = ab

bc + ac = ab

bc – ab = -ac

b(c-a) = -ac

b = -ac/(c-a)

aznul

said:Diberi L= m(1+5n)/1-n,

cari nilai L apabila m=9 dan n=1/6

unclezul

said:Gantikan nilai m dan n mengikut nilai yang diberi.

L=9(1+5(1/6))/1-(1/6)

= 9(6/6 + 5/6) / 6/6 – 1/6

= 9x(11/6)x(6/5)

= 99/5

amirah

said:diberi 6ef + 2en – 12mf – 4mn (Faktorkan setiap yang berikut)

Ling Ling

said:(6ef+2en)(-12mf-4mn)=2e(3f+n)-4m(3f+n)

=(2e-4m)(3f+n)

amirah

said:macam mana nak selesaikan ungkapan 1/2 (8 – 4uv^2) + 1/3 (9uv^2 – 3) dan

20xy-15w/5 – 2(8-w+xy)

Nadzirah

said:Can you help me to factorise this algrebric expression ,

pq – 6q + 6p – 36.

unclezul

said:q (p-6)+6 (p-6) = (q+6)(p-6)

sasha

said:(f+5g)(f-3g)

unclezul

said:f ( f-3g ) + 5g ( f-3g ) =

f^ 2 -3fg + 5fg- 15g ^ 2 =

f^ 2 + 2fg -15 g^ 2

sasha

said:(2p_7)(q+2)

I dono Hw to solve like tiz questions all

Ying Ying

said:Given that 1/2yz-x=(xy+4z)/3, how should I find z in the terms of x and y?