Tags
addition & subtraction, algebraic expression, multiplication & division, power & roots of a number
ALGEBRAIC EXPRESSION
Did you ever realise that the following expression could be expanded as follows :
MULTIPLICATION & DIVISION
xyz = x.y.z (multiplication concept)
2m²k³/mk = 2.m.m.k.k.k/m.k (multiplication & division concept)
= 2.m.m.k.k.k/m.k
= 2mk²
ADDITION & SUBTRACTION
- Apply the principle of similar objects as basis of addition & subtraction. This principle being taught at the primary school level, where only similar objects could be added or deducted ( the case of 2 cars + 1 car = 3 cars & 1 car + 1 lorry = 1 car + 1 lorry)
4x²y – x²y = (4 – 1) x²y
= 3x²y
mk³n/3 + 2mnk³/3 = (1/3 + 2/3)mnk³
= (3/3)mnk³
= mnk³
MIXED OPERATION
4j²k – 6j³k²m/3jkm = 4j²k – [6.j.j.j.k.k.m/3.j.k.m]
= 4j²k – [2 6.j.j.j.k.k.m/3.j.k.m]
= 4j²k – 2j²k
= (4 – 2)j²k
= 2j²k
FINDING THE VALUE OF UNKNOWN
- This sub-topic could be easily dealt by applying our understanding of addition, subtraction, multiplication & division that we have learnt from Primary School level. For instance; ___ + 3 = 5 is actually the same with ___ = 5 – 3 or 12 ÷ 3 = 4 is actually the same with 12 = 4 x 3 …. movement of numbers from one side to another which results in changes of value ( + to -, x to ÷ , ² to √ and vice versa )
From the given expression of 4m²k/5 = 4; find the value of m?
4m²k/5 – 6 = 4
By retaining m on the left side, we now move the rest of the numbers to the right side ( be sure that the value of m must be + at all time)
4m²k/6 = 4 + 6 = 10
4m²k = 10.6 = 60
m² = 60/4.k = 15/k
m = √(15/k)
